Function _run_module_as_main

Lib/runpy.py:172–197

Runs the designated module in the __main__ namespace Note that the executed module will have full access to the __main__ namespace. If this is not desirable, the run_module() function should be used to run the module code in a fresh namespace. At the very least, these v

(mod_name, alter_argv=True)

# creation when run_module() no longer met the needs of
# mainmodule.c, but couldn't be changed because it was public)
def _run_module_as_main(mod_name, alter_argv=True):
    """Runs the designated module in the __main__ namespace

       Note that the executed module will have full access to the
       __main__ namespace. If this is not desirable, the run_module()
       function should be used to run the module code in a fresh namespace.

       At the very least, these variables in __main__ will be overwritten:
           __name__
           __file__
           __loader__
           __package__
    """
    try:
        if alter_argv or mod_name != "__main__": # i.e. -m switch
            mod_name, mod_spec, code = _get_module_details(mod_name, _Error)
        else:          # i.e. directory or zipfile execution
            mod_name, mod_spec, code = _get_main_module_details(_Error)
    except _Error as exc:
        msg = "%s: %s" % (sys.executable, exc)
        sys.exit(msg)
    main_globals = sys.modules["__main__"].__dict__
    if alter_argv:
        sys.argv[0] = mod_spec.origin
    return _run_code(code, main_globals, None,
                     "__main__", mod_spec)

def run_module(mod_name, init_globals=None,
               run_name=None, alter_sys=False):