Method notify

Lib/asyncio/locks.py:317–331

By default, wake up one task waiting on this condition, if any. If the calling task has not acquired the lock when this method is called, a RuntimeError is raised. This method wakes up n of the tasks waiting for the condition variable; if fewer than n are waiting, t

(self, n=1)

        return result

    def notify(self, n=1):
        """By default, wake up one task waiting on this condition, if any.
        If the calling task has not acquired the lock when this method
        is called, a RuntimeError is raised.

        This method wakes up n of the tasks waiting for the condition
         variable; if fewer than n are waiting, they are all awoken.

        Note: an awakened task does not actually return from its
        wait() call until it can reacquire the lock. Since notify() does
        not release the lock, its caller should.
        """
        if not self.locked():
            raise RuntimeError('cannot notify on un-acquired lock')
        self._notify(n)

    def _notify(self, n):
        idx = 0