Function make_model_tuple

django/db/models/utils.py:5–25

Take a model or a string of the form "app_label.ModelName" and return a corresponding ("app_label", "modelname") tuple. If a tuple is passed in, assume it's a valid model tuple already and return it unchanged.

(model)

def make_model_tuple(model):
    """
    Take a model or a string of the form "app_label.ModelName" and return a
    corresponding ("app_label", "modelname") tuple. If a tuple is passed in,
    assume it's a valid model tuple already and return it unchanged.
    """
    try:
        if isinstance(model, tuple):
            model_tuple = model
        elif isinstance(model, str):
            app_label, model_name = model.split(".")
            model_tuple = app_label, model_name.lower()
        else:
            model_tuple = model._meta.app_label, model._meta.model_name
        assert len(model_tuple) == 2
        return model_tuple
    except (ValueError, AssertionError):
        raise ValueError(
            "Invalid model reference '%s'. String model references "
            "must be of the form 'app_label.ModelName'." % model
        )


def resolve_callables(mapping):