Function get_versions

pandas/_version.py:643–692

Get version information or return default if unable to do so.

()

def get_versions() -> dict:
    """Get version information or return default if unable to do so."""
    # I am in _version.py, which lives at ROOT/VERSIONFILE_SOURCE. If we have
    # __file__, we can work backwards from there to the root. Some
    # py2exe/bbfreeze/non-CPython implementations don't do __file__, in which
    # case we can only use expanded keywords.

    cfg = get_config()
    verbose = cfg.verbose

    try:
        return git_versions_from_keywords(get_keywords(), cfg.tag_prefix, verbose)
    except NotThisMethod:
        pass

    try:
        root = os.path.realpath(__file__)
        # versionfile_source is the relative path from the top of the source
        # tree (where the .git directory might live) to this file. Invert
        # this to find the root from __file__.
        for _ in cfg.versionfile_source.split("/"):
            root = os.path.dirname(root)
    except NameError:
        return {
            "version": "0+unknown",
            "full-revisionid": None,
            "dirty": None,
            "error": "unable to find root of source tree",
            "date": None,
        }

    try:
        pieces = git_pieces_from_vcs(cfg.tag_prefix, root, verbose)
        return render(pieces, cfg.style)
    except NotThisMethod:
        pass

    try:
        if cfg.parentdir_prefix:
            return versions_from_parentdir(cfg.parentdir_prefix, root, verbose)
    except NotThisMethod:
        pass

    return {
        "version": "0+unknown",
        "full-revisionid": None,
        "dirty": None,
        "error": "unable to compute version",
        "date": None,
    }