Method abs

pandas/core/generic.py:1507–1575

Return a Series/DataFrame with absolute numeric value of each element. This function only applies to elements that are all numeric. Returns ------- abs Series/DataFrame containing the absolute value of each element. See Also ---

(self)

    @final
    def abs(self) -> Self:
        """
        Return a Series/DataFrame with absolute numeric value of each element.

        This function only applies to elements that are all numeric.

        Returns
        -------
        abs
            Series/DataFrame containing the absolute value of each element.

        See Also
        --------
        numpy.absolute : Calculate the absolute value element-wise.

        Notes
        -----
        For ``complex`` inputs, ``1.2 + 1j``, the absolute value is
        :math:`\\sqrt{ a^2 + b^2 }`.

        Examples
        --------
        Absolute numeric values in a Series.

        >>> s = pd.Series([-1.10, 2, -3.33, 4])
        >>> s.abs()
        0    1.10
        1    2.00
        2    3.33
        3    4.00
        dtype: float64

        Absolute numeric values in a Series with complex numbers.

        >>> s = pd.Series([1.2 + 1j])
        >>> s.abs()
        0    1.56205
        dtype: float64

        Absolute numeric values in a Series with a Timedelta element.

        >>> s = pd.Series([pd.Timedelta("1 days")])
        >>> s.abs()
        0   1 days
        dtype: timedelta64[us]

        Select rows with data closest to certain value using argsort (from
        `StackOverflow <https://stackoverflow.com/a/17758115>`__).

        >>> df = pd.DataFrame(
        ...     {"a": [4, 5, 6, 7], "b": [10, 20, 30, 40], "c": [100, 50, -30, -50]}
        ... )
        >>> df
             a    b    c
        0    4   10  100
        1    5   20   50
        2    6   30  -30
        3    7   40  -50