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Function join_condition

lib/sqlalchemy/sql/util.py:95–128  ·  view source on GitHub ↗

Create a join condition between two tables or selectables. e.g.:: join_condition(tablea, tableb) would produce an expression along the lines of:: tablea.c.id == tableb.c.tablea_id The join is determined based on the foreign key relationships between the two selec

(
    a: FromClause,
    b: FromClause,
    a_subset: Optional[FromClause] = None,
    consider_as_foreign_keys: Optional[AbstractSet[ColumnClause[Any]]] = None,
)

Source from the content-addressed store, hash-verified

93
94
95def join_condition(
96 a: FromClause,
97 b: FromClause,
98 a_subset: Optional[FromClause] = None,
99 consider_as_foreign_keys: Optional[AbstractSet[ColumnClause[Any]]] = None,
100) -> ColumnElement[bool]:
101 """Create a join condition between two tables or selectables.
102
103 e.g.::
104
105 join_condition(tablea, tableb)
106
107 would produce an expression along the lines of::
108
109 tablea.c.id == tableb.c.tablea_id
110
111 The join is determined based on the foreign key relationships
112 between the two selectables. If there are multiple ways
113 to join, or no way to join, an error is raised.
114
115 :param a_subset: An optional expression that is a sub-component
116 of ``a``. An attempt will be made to join to just this sub-component
117 first before looking at the full ``a`` construct, and if found
118 will be successful even if there are other ways to join to ``a``.
119 This allows the "right side" of a join to be passed thereby
120 providing a "natural join".
121
122 """
123 return Join._join_condition(
124 a,
125 b,
126 a_subset=a_subset,
127 consider_as_foreign_keys=consider_as_foreign_keys,
128 )
129
130
131def find_join_source(

Callers 1

_determine_joinsMethod · 0.85

Calls 1

_join_conditionMethod · 0.80

Tested by

no test coverage detected